The first, sulfuric acid, is a strong acid and oxidative / corrosive in 4% solution
The second, acetic acid, is a weak acid and consumable in 4% solution (vinegar)
AnswerHCOOH -------H2SO4------------> CO + H2O
This was asked in a coursework paper to my sister and she could not find an answer ..so far neither can I...I did find where it gave off hydrogen in a reaction..not sure on t6his hehe it may be CH3-CO-Cl + H2 = CH3-CO-H + HCl
Isopropyl alcohol on oxidation forms acetone, but the further oxidation on heating produces acetic acid , carbon dioxide and water.CH3-CHOH-CH3 ------K2Cr2O7/H2SO4-----> CH3-CO-CH3 + H2OBalanced:K2Cr2O7 + 3 CH3CHOHCH3 + 4 H2SO4 --> 3 CH3COOH + Cr2(SO4)3 + K2SO4 + 4 H2O
Acetyl acetic acid is CH3-CO-CH2-COOH
CH3-(CH2)2-CO-OH with a double bond between the carbon and oxygen (the carbon and the alcohol is a single bond).
The chemical reaction is: 4 H3BO3 + 2 NaOH = Na2B4O7 + 7 H2O
What is the difference between an independent co-executor and a co-executor
AnswerHCOOH -------H2SO4------------> CO + H2O
when two similar alkyl or aryl groups are attached to carbonyl carbons then it is a symmetrical ketone..... as CH3-CO-CH3 or C6H5-CO-C6H5
It is, CH3-CO-Cl
PENTAN-3-EN-2-ONE
The products are Acetone CH3-CO-CH3 and Formaldehyde CH2O.
2-propanone. The oxygen is doube bonded to the second carbon.
This was asked in a coursework paper to my sister and she could not find an answer ..so far neither can I...I did find where it gave off hydrogen in a reaction..not sure on t6his hehe it may be CH3-CO-Cl + H2 = CH3-CO-H + HCl
Ph-O-CH2-CO-CH3
An acetylamino is the univalent radical CH3-CO-NH- derived from acetamide.
Isopropyl alcohol on oxidation forms acetone, but the further oxidation on heating produces acetic acid , carbon dioxide and water.CH3-CHOH-CH3 ------K2Cr2O7/H2SO4-----> CH3-CO-CH3 + H2OBalanced:K2Cr2O7 + 3 CH3CHOHCH3 + 4 H2SO4 --> 3 CH3COOH + Cr2(SO4)3 + K2SO4 + 4 H2O