Dist2 = [2 - (-5)]2 + [7 - 0]2 = 72 + 72 = 2*72
So dist = 7*sqrt(2) = 9.8995
There is a distance of 3 between -3 and 0.
Using the Law of Pythagoras, you get square root of (62 + 72).The distance between the origin and the point ( -6, 7 ) is ~9.22To find the distance, we use the distance formula.c2 = a2 + b2This is an adaptation from the Pythagorean theorem. In this case, a is the difference in x coordinates; b the difference in y.The Cartesian origin is at ( 0, 0 ). So...c2 = ( -6 - 0 )2 + ( 7 - 0 )2c2 = -62 + 72c2 = 36 + 49c2 = 85c =~ 9.22
a2 + 7a - 8a2 = 6a7 ∴ a2 + 7a - 8a2- 6a7 = 0 ∴ a + 7 - 8a - 6a6 = 0 ∴ 7 - 7a - 6a6 = 0 ∴ 6a6 + 7a - 7 = 0
Let the inputs be A2 A1 A0 & outputs be S5 S4 S3 S2 S1 S0. Now, make a truth table as follows A2 A1 A0 S5 S4 S3 S2 S1 S0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 0 0 0 1 0 0 and so on....... Finally we'll get S0 = A0 S1 = 0 S2 = A1 A2(bar) S3 = A0 [ A1 XOR A2] S4 = A2 [A1(bar) + A0 ] S5 = A1 A2
The distance is 0.
There is a distance of 3 between -3 and 0.
ax + by + cz + d = 0At the z-intercept, 'x' and 'y' are both zero.cz + d = 0 --> z = -d/c --> The z-intercept is the point (0, 0, -d/c).At the x-intercept, 'y' and 'z' are zero.ax + d = 0 --> x = -d/a --> The x-intercept is the point (-d/a, 0, 0).The distance between the points (0, 0, -d/c) and (-d/a, 0, 0) issqrt[ (-d/a)2 + (-d/c)2 ] = sqrt (d2/a2 + d2/c2) = d sqrt(1/a2 + 1/c2)
Using the Law of Pythagoras, you get square root of (62 + 72).The distance between the origin and the point ( -6, 7 ) is ~9.22To find the distance, we use the distance formula.c2 = a2 + b2This is an adaptation from the Pythagorean theorem. In this case, a is the difference in x coordinates; b the difference in y.The Cartesian origin is at ( 0, 0 ). So...c2 = ( -6 - 0 )2 + ( 7 - 0 )2c2 = -62 + 72c2 = 36 + 49c2 = 85c =~ 9.22
Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )
a2 + 7a - 8a2 = 6a7 ∴ a2 + 7a - 8a2- 6a7 = 0 ∴ a + 7 - 8a - 6a6 = 0 ∴ 7 - 7a - 6a6 = 0 ∴ 6a6 + 7a - 7 = 0
Let the inputs be A2 A1 A0 & outputs be S5 S4 S3 S2 S1 S0. Now, make a truth table as follows A2 A1 A0 S5 S4 S3 S2 S1 S0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 0 0 0 1 0 0 and so on....... Finally we'll get S0 = A0 S1 = 0 S2 = A1 A2(bar) S3 = A0 [ A1 XOR A2] S4 = A2 [A1(bar) + A0 ] S5 = A1 A2
The distance is 0.
The distance is 0.
Distance from (0, 0) to (5, 12) using distance formula is 13
The distance between objects and the different is 0. The distance between the mass and an object is 1.
a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c
5.75