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Let us name the coordinates, to be easy to work and follow the answer:Point 1: x1=2 y1=4
Point 2: x2=-1 y2=-3
In general, you can alwaysplace two differentpoints (that are not at the same vertical or horizontal) on the Cartesian coordinate system,placed at the 2 non-rectangularcorners of a rectangular triangle, see the "drawing" below:
1
|\
| \
| \
+---2
The distance between two points is (using thePitagorastheorem):
distance2 = (x1-x2)2 + (y1-y2)2
In your case,
distance2= (2-(-1))2 + ((-1)-(-3))2
therefore,
distance2= (2+1)2+ (-1+3)2
distance2= 32 + (-2)2
distance2= 9+ 4
distance2= 13
Finally,
the distance is the square root of 13 =3.6 (approximately).
Wiki User
∙ 11y ago
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8.54
