1 minute = 60 seconds
9.1 minutes = (9.1 x 60) = 546 seconds
Distance = (speed) x (time) = (2.3 m/s) x (546 sec) = 1,255.8 meters
As the acceleration is uniform, the train has an average speed that is half the difference between the start and final velocities, which in this case is half the final velocity. 1 hr = 60 min 1 km/h = 1 km ÷ 1 hr = km ÷ 60 min = 1/60 km/min Distance = velocity × time = (½ × 72 × 1/60 km/min) × (5 min) = 36/60 × 5 km = 3 km
False.
Velocity = Radius x RPM For example if a body of 32 Inches in diameter rotating at 3600 rpm, the velocity is calculated by Velocity = 32/2 * 3600 Velocity = 57,200 inches per minute Velocity = 57,200 Inches/min * 60 Min/Hr * 1ft/12in * 1 mi/5280 ft Velocity = 54.5 miles per hr
Convert the velocity Vmax from ΔA/min to nmol/min (milliunits, mU). For example: 1 Unit = 1 U = 1 μmol PNP formed per min 1 milli-Unit = 1 mU = 1 nmol PNP formed per min Extinction coefficient ε for PNP at 410 nm = 15,000 M-1 cm-1 And the pathlength = 0.34 cm if the velocity v is determined to be 0.294 ∆A/min (absorbance units per min), then: 0.294 ∆A /min * M/(15,000 A * 0.34 cm) = 0.0000196 M/min = 19.6 μM/min = = 19.6 μmol / (liter * min) = 0.0196 μmol / (ml * min) The enzymatic reaction was carried out in 250 μl solution, hence the velocity of the enzyme is 0.0196 μmol / (ml * min) * 0.25 ml = 0.0049 μmol/min = 4.9 nmol/min PNP generated. v = 4.9 nmol/min = 4.9 mU
distance = rate * time 80 km = r * 38 minute r = 80 km / 38 min * 1000 m/km * 60 seconds/minute = 4800000/38 ~= 126315.79 m/s
As the acceleration is uniform, the train has an average speed that is half the difference between the start and final velocities, which in this case is half the final velocity. 1 hr = 60 min 1 km/h = 1 km ÷ 1 hr = km ÷ 60 min = 1/60 km/min Distance = velocity × time = (½ × 72 × 1/60 km/min) × (5 min) = 36/60 × 5 km = 3 km
It depends upon the speed or velocity of the car for e.g. if speed is 100km/min then Distance = speed X time i.e. D= 100X90= 9000km
The measure of 120 km is not a measure of velocity, so that the question is wrongly formulated. I assume that the right measure for velocity is 120 km/h. In this case in 3 min (that are 1/20 of an hour) the considered object travels 6 km.
False.
i think its velocity is min n its try to attain max. velocity which is terminal velocity...what say?
Ft/min
The definition of velocity, or at least speed, is distance/(time at speed), in this instance 10/9 km/min. (In advanced mathematics, "velocity" is a vector quantity, with both a magnitude and a direction. In that instance, a direction would also be needed but was not stated in the problem.)
60 km * 3 = 180 km 45 min * 4 = 180 min 180km/180hr = 1 km/min 1km = 1000m 1 min = 60s 1000m/60s = 16.67 m/s
Velocity = Radius x RPM For example if a body of 32 Inches in diameter rotating at 3600 rpm, the velocity is calculated by Velocity = 32/2 * 3600 Velocity = 57,200 inches per minute Velocity = 57,200 Inches/min * 60 Min/Hr * 1ft/12in * 1 mi/5280 ft Velocity = 54.5 miles per hr
Convert the velocity Vmax from ΔA/min to nmol/min (milliunits, mU). For example: 1 Unit = 1 U = 1 μmol PNP formed per min 1 milli-Unit = 1 mU = 1 nmol PNP formed per min Extinction coefficient ε for PNP at 410 nm = 15,000 M-1 cm-1 And the pathlength = 0.34 cm if the velocity v is determined to be 0.294 ∆A/min (absorbance units per min), then: 0.294 ∆A /min * M/(15,000 A * 0.34 cm) = 0.0000196 M/min = 19.6 μM/min = = 19.6 μmol / (liter * min) = 0.0196 μmol / (ml * min) The enzymatic reaction was carried out in 250 μl solution, hence the velocity of the enzyme is 0.0196 μmol / (ml * min) * 0.25 ml = 0.0049 μmol/min = 4.9 nmol/min PNP generated. v = 4.9 nmol/min = 4.9 mU
The distance is 8.2 miles in 12 min with a current traffic: 14 min
You measure the distance travelled and convert it to feet. You measure the time taken for travelling that distance and convert that it to minutes. You divide the first by the second and you have feet per minute.