pH would decrease since H+ concentration increases, while pOH would increase since OH- concentration decreases.
But pH would always be above 7 and pOH would always be below 7
since H+ will never be equal to OH-
[OH-] would be always be greater than [H+] in any solution of NaOH , however dilute.
Also remember pH + pOH =14, thus if pH decreases then pOH increases.
Thanking you
Yours Rajiv
the pH decreases since dilution affects the cocentration of H+ found ... thus the pH so the more the water is , the less the concentration of H+ is for the same amount of H+
-log(10^-4 M NaOH) = 4 14 - 4 = 10 pH NaOH -----------------------
3
As NaOH is a strong base I would not be surprised to see a 14 pH at least.
The pH value for this solution is 13.
the pH decreases since dilution affects the cocentration of H+ found ... thus the pH so the more the water is , the less the concentration of H+ is for the same amount of H+
You dont - adding NaOH increases pH.
1 millimolar = 0.001 M NaOH ( a base, remember ) - log(0.001 M NaOH) = 3 14 - 3 = 11 pH ----------
dilution will reduce the viscosity The effect of dilution on viscosity of oil is that it will decrease.
-log(10^-4 M NaOH) = 4 14 - 4 = 10 pH NaOH -----------------------
3
As NaOH is a strong base I would not be surprised to see a 14 pH at least.
HCl : makes it acidic. it decreases the pH NaOH : makes it alkaline. it increases the pH
The pH value for this solution is 13.
Sodium hydroxide, NaOH, has a very high pH, so it can be used to raise the pH of some mixture that is too acidic.
Supposed the acid and base are both strong: pH of the acid is 0.0 and the pH of the base (hydroxide) is 14.0
A 0.01 M solution of NaOH has a pH =13