What is an Elastic Limit?

Answer 1

Determine the minimum diameter a steel wire can have if it is to support a 70 kg person. without exceeding the elastic limit of steel which is 5 x 108

Pa.

a lim= F/A = 5 × 108

Pa

A = F/a lim

but F = W = mg and A = pi r

2 = pi (d/2)2

d = sqr[(4/pi) × (m g / a B)]

d = sqr[(4/pi) × (70 kg × 9.81 m/s2

/5 × 10^8

Pa)] = 1.3 × 10^-3

m = 1.3 mm

Answer 2

The maximum stress at which the material will undergo elastic strain (recoverable deformation). At stress above this, plastic strains will occur (permanent deformation). Depending on the confining stress and tempreature as plastic deformations occur the rock will either fail in a brittle manner (fractures will propagate through the material - this occurs at low confining stresses and high strain rates) or will deform in a ductile manner (like squashing plasticine which occurs at low strain rates, high confining stresses and high temperatures).

Answer 3

The elasticity of steel is like and elastic band once the force is exceeded it BREAKS! HAHAHAHAHAHAHAHAHAHAHAHAHAHA

Answer 4

E - young's modulus

G - Shear modulus

K - Bulk modulus

not sure about a forth but the Poisson's ratio is important

Answer 5

The furthest an object can stretch before it passes the point of being able to return to its original size.