1s2 2s2 2p4
Orbital 'fill up' of Oxygen (atom number 8) (K) = 2 electrons (L) = 6 electrons
The electron configuration of gallium is: [Ar]3d104s24p1.
Two, unless an oxygen atom is bonded to another oxygen atom or to a fluorine atom.
Electron Configuration
Electron configuration of radium:Ra: [Rn]7s2Ra(2+): 1s2.2s2.2p6.3s2.3p6.3d10.4s2.4p6.4d1o.4f14.5s2.5p6.5d10.6s2.6p6.
The electron configuration of oxygen in the oxide ion (O2-) is 1s2 2s2 2p6 (equivalent to the configuration of a neon atom), as the oxide ion has gained two extra electrons compared to a neutral oxygen atom.
2, 6 or 1s2, 2s2, 2p6
Orbital 'fill up' of Oxygen (atom number 8) (K) = 2 electrons (L) = 6 electrons
An oxygen atom only forms two covalent bonds with a hydrogen atom because oxygen needs to gain two electrons to achieve a stable electron configuration, similar to the noble gas configuration. By sharing one electron with each hydrogen atom, oxygen can fulfill its octet and achieve stability.
Electron configuration for an atom is the distribution of electrons on atomic orbitals.
The electron configuration for an oxygen atom is 1s^2 2s^2 2p^4. This means there are 8 electrons in total, with 2 electrons in the 1s orbital, 2 in the 2s orbital, and 4 in the 2p orbital.
The electron configuration of an atom with electrons in the dz2 orbital is 3d10.
Yes, oxygen has a relatively high ionization energy because it requires a large amount of energy to remove an electron from an oxygen atom due to its stable electron configuration.
The electrons configuration for O2- is [He]2s22p6.
The electron configuration of a chromium atom is 1s2 2s2 2p6 3s2 3p6 4s1 3d5.
The ions of elements nitrogen (N3-), oxygen (O2-), and fluorine (F-) will have the same electron configuration as a sodium ion (Na+), which is the same as the electron configuration of the noble gas neon.
If a sodium atom loses an electron to become a Na+ ion, its electron configuration will be the same as neon (1s22s22p6). Both sodium and neon have stable electron configurations.