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Answered 2011-09-27 01:59:04

the empirical formula for fluorine is F. the chemical formula is F2.

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The Empirical Formula for sodium and fluorine is NaF, because Na has a +1 charge and F has a -1 charge which cancel each other out.


Magnesium usually forms divalent cations and fluorine usually forms monovalent anions. Therefore, the predicted empirical formula is MgF2.




The compounds of oxygen with fluorine are:OF2, O2F2, O3F2


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No. It is molecular formula. Its empirical formula will be CH2O.



A molecular formula is identical to the empirical formula, and is based on quantity of atoms of each type in the compound.The relationship between empirical and molecular formula is that the empirical formula is the simplest formula, and the molecular can be the same as the empirical, or some multiple of it. An example might be an empirical formula of C3H8. Its molecular formula may be C3H8 , C6H16, C9H24, etc. Looking at it the other way, if the molecular formula is C6H12O6, the empirical formula would be CH2O.


Molecular formula: c6h12o6 Empirical formula: CH2O


CH will be the empirical formula and C12H12 will be the molecular formula



An empirical formula has no data about the structure of a compound.


The empirical formula tells you the simplest formula for the compound. The molecular formula will be some multiple of the empirical formula, or it can be identical to the empirical formula.


The empirical formula is:- C4H6O6


what is the empirical formula for water H2O



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