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Answered 2011-09-27 01:59:04

the empirical formula for fluorine is F. the chemical formula is F2.


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The Empirical Formula for sodium and fluorine is NaF, because Na has a +1 charge and F has a -1 charge which cancel each other out.

Magnesium usually forms divalent cations and fluorine usually forms monovalent anions. Therefore, the predicted empirical formula is MgF2.

The compounds of oxygen with fluorine are:OF2, O2F2, O3F2

Yes, this is an empirical formula.

It is an empirical formula.

C2N2H8 is an empirical formula !

C4H2O is the empirical formula

CuSO4 is an empirical formula.

C6H6O2is an empirical formula.

H2SO4 is an empirical formula.

The empirical formula is CH5.

SO3 is an empirical formula !

No. It is molecular formula. Its empirical formula will be CH2O.

A molecular formula is identical to the empirical formula, and is based on quantity of atoms of each type in the compound.The relationship between empirical and molecular formula is that the empirical formula is the simplest formula, and the molecular can be the same as the empirical, or some multiple of it. An example might be an empirical formula of C3H8. Its molecular formula may be C3H8 , C6H16, C9H24, etc. Looking at it the other way, if the molecular formula is C6H12O6, the empirical formula would be CH2O.

Molecular formula: c6h12o6 Empirical formula: CH2O

CH will be the empirical formula and C12H12 will be the molecular formula

An empirical formula has no data about the structure of a compound.

The empirical formula tells you the simplest formula for the compound. The molecular formula will be some multiple of the empirical formula, or it can be identical to the empirical formula.

The empirical formula is:- C4H6O6

what is the empirical formula for water H2O

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