The first ionization of aluminum is Al(g) -> Al+(g) + e-
Al+ ---> Al+2 + e-
Al+ - e- ------> Al2+
Al+2(g) --> Al+3(g) + e-1
2
2Al + 3S -> Al2S3
C
The chemical formula that represents this is below:3K2SO4 + 2AlCl3 --> 6KCl + Al2(SO4)3
CH3CH2NH2+H2O⇌CH3CH2NH3++OH−
a=b=c
I can get started on that just as soon as you show me the equation.
SinA/a = SinB/b = SinC/c
2Al + 3S -> Al2S3
2Al + 3S -> Al2S3
x^2 + y^2 = 100
C
mg+ 2e
The chemical formula that represents this is below:3K2SO4 + 2AlCl3 --> 6KCl + Al2(SO4)3
M + ionization energy à M1+ + e- M + ionization energy à M1+ + e-
Hg(g) -> Hg^+(g) + e^-
CH3CH2NH2+H2O⇌CH3CH2NH3++OH−
uh2