The equation of a circle through the center (using "^" for power) is:
x^2 + y^2 = r^2
To have the center anywhere else, say, through point (a, b), just replace "x" with "x-a" (in this case: x - 1), and "y" with "y-b" (in this case: y - -1, or y + 1).
3.14 x 1
This makes no sence
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1
The equation is: (x+1)^2 +(y+5)^2 = 36
(x - 1)2 + (y + 1)2 = 1
(x + 2)2 + (y - 2)2 = 1
(x + 2)2 + (y - 2)2 = 1
It is (x - 1)^2 + (y - 1)^2 = 5^2
(x-3)2 + (y-1)2 = 42
(x + 1)2 + (y + 5)2 = 36