HCO3^-(aq)+H2O(l)--->H2CO3(aq)+OH^-(aq)
The equation for the reaction of benzoic acid and NaHCO3 is as follows: C6H5COOH + NaHCO3 ===> C6H5COO-Na+ + H2O + CO2
C6H5COO^-(aq) + H20(l) + CO2(g) + Na^+(aq)
sodium ion being the spectator ion for this reaction
C6H5COOH(aq) + NaHCO3(aq) --> C6H5COO^-(aq) + Na^+(aq) + H2O(l) + CO2(g)
Benzoic acid is a weak acid and NaHCO3 is a weak base. The reaction is a typical acid-base reaction.
yes it does
CH3cooh + NAHCO3
Benzoic acid has a chemical formula of PhCOOH. It does not react with water so much as it dissociates in it, forming a free hydrogen ion. The reaction for the dissociation is PhCOOH(aq) --> PhCOO-(aq) + H+ (aq).
what is the reaction of benzoic acid with sodium bicarbonate
the oxygen of the zinc will combine with acid group of the acid as the ZnOis basic in nature
NaHCO3 + HCl --> NaCl + H2O + CO2
CH3cooh + NAHCO3
C6H5COOH + NaHCO3 ===> C6H5COO-Na+ + H2O + CO2
Benzoic acid has a chemical formula of PhCOOH. It does not react with water so much as it dissociates in it, forming a free hydrogen ion. The reaction for the dissociation is PhCOOH(aq) --> PhCOO-(aq) + H+ (aq).
what is the reaction of benzoic acid with sodium bicarbonate
the oxygen of the zinc will combine with acid group of the acid as the ZnOis basic in nature
NaHCO3 + HCl --> NaCl + H2O + CO2
CH3COOH + NaHCO3 = CH3COO-Na+ + H2O + CO2
The reaction for benzoic acid and methyl amine produces benzamide. The equation is C6H5COOH + CH3NH2 ---> C6H5CONHCH3 + H2O.
HCl + NaHCO3 ---> NaCl + H2O + CO2
K2CO3 + 2 benzoic acid -> 2 potassium benzoate + H2CO3
NaHCO3 + HCl = CO2 + H2O + NaCl
2 NaHCO3 + H2SO4 --> Na2SO4 + 2CO2 + 2H20