If you mean points of (-3, 2) and (5, -5) then the equation works out as 8y = -7x-5
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x
Points: (-2, 2) and (3, 4) Slope: 2/5
y = 2/3x+4 or in the general form of sraight line equation as 2x-3y+12 = 0
Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11
Choose the equation of the line that contains the points (1, -1) and (2, -2).
Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
Slope: 5 Points: (-2, -3) Equation: y = 5x+7
If you mean points of: (10, -2) and (20, -12) then it is a straigh line equation in the form of y = -x+8
Points: (4, -4) and (-2, 0) Slope: -2/3 Equation: y = -2/3x-4/3 or as 3y = -2x-4
Points: (4, -2) and (-5, -2) Slope: (-2--2)/(-5-4) = 0 Equation: y = -2 which will be a staight line parallel to the x axis
Equation of the straight line: y = -3/5x+2 in slope intercept form
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
A line contains at least 2 points.
If you mean points of (2, -8) and (0, 0) then the equation is y = -4x
Answer this question… What is the slope of the line that contains the points (-1, 2) and (4, 3)?