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Molarity of products divided by reactants Keq=(products)/(reactants)
Theres usually a letter for the cup size eg.aaa,aa,a,b,c,d,dd,e,f,g,e etc.Then theres the band size, which differs which country you are in30,32,34,36,38,40 etc. (English)
DD North-East was created in 1992.
A dominant genotype is represented as DD or Dd but with many different letters. The DD is a homozygous dominant, while the Dd is the heterozygous dominant. Recessive is always represented as dd or rr or whatever letter you want to use. It is always homozygous recessive. There can never be a heterozygous recessive.
If the gene for a trait has two alleles, one dominant (D) and one recessive (d) there are three possible combinations in the genotype: DD (homozygous dominant) Dd (heterozygous) dd (homozygous recessive)
AA BBCC DD These are rhyming couplets reflecting the running however tetrameter is also used.
If K(equilibrium constant) is greater than Q(concentration constant at a prticular point) then the reaction will tend to the right. If Q is less that K the reverse reaction will occur and if they are equal the reaction is at equilibrium. Example: aA+bB<--->cC+dD K=1.5 if Q<1.5 the reaction is aA + bB ---> cC + dD if Q> 1.5 the reaction is aA + bB <--- cC + dD K= [C]c[D]d/ [A]a[B]b at any point Q=[C]c[D]d/ [A]a[B]b at a particular point in time
Molarity of products divided by reactants Keq=(products)/(reactants)
dd aa bb a, gg ff ee d. aa gg ff e, dd aa bb a, gg ff ee d.
dd aa bb a gg fe eed aagg ffe aa gg ff e dd aa bba gg ffee d
GG high DD EE high D CC BB AA G high DD CC BB A DD CC BB A GG high DD EE high D CC BB AA G
AA bb gg cc bb cc dd AA bb cc dd ee gg times two hope i help
dd AA BB a- GG ff# EE d- AA GG ff# e- AA GG ff# e- dd AA BB a- GG ff# EE d-
Aabbccdd eeffgghh
C f ef a g fg agf f a cd dc aa fg fg agf dd c f dc aa fg fg dc aa cd dc aa fg fg agf dd c f
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Cross each allele separately to get the final genotype: AA x Aa = AA, aa, Aa, Aa .: 1/2 Bb x BB = BB, BB, Bb, Bb .: 1/2 cc x CC = Cc .: 1 Dd x dd = DD, dd, Dd, Dd .: 1/2 Ee x Ee = EE, Ee, Ee, ee .: 1/4 FF x ff = Ff, Ff, Ff, Ff .: 1 Multiply all probable fractions: 1/2 x 1/2 x 1 x 1/2 x 1/4 x 1 = 1/64 chance of that specific genotype.