GCF(Y, Y) = Y.
If that's y2, the answer is (y - 5)(y + 3)
(y + 3)(y - 10)
That depends on the numerical value of Y.
x2-y2=(x-y)(x+y) which is a well known identity.
X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)
1 and Y
The GCF is Y.
The GCF is Y.
GCF(Y, Y) = Y.
All you can do to factor that expression is to divide both terms by y: y2 + 4y = y(y + 4)
GCF(Y, Y) = Y.
y(y + 4)
y(y-3)(y+3)
(y + 8)(y - 7)
To factor out the expression: x2y-y3 First factor out one "y": y(x2-y2) The expression x2-y2 is a difference of squares, which factors as well: (y)(x-y)(x+y) This is the simplest factoring of the original expression.
Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)