(b - x)(ab - xy)
linear
(a + 2b)(a + 2b)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
Arthur Pythagoras he say AB2 = AC2 + BC2, so AB2 = 81 + 144 ie AB = sqrt 225 = 15 cm
Two is a prime factor of that equation.
4
ab2
√(ab2) = (√a)*b
If you mean (Ab)2 then it is Ab, but if you mean Ab2 then it is square root (A)(b).
(a -b) · (a2+ab+b2) = (a3+a2b+ab2) - (a2b+ab2+b3) = a3 -b3 (a+b) · (a2 -ab+b2) = (a3 -a2b+ab2) +(a2b -ab2+b3) = a3+b3 More generally: (a ∓ b) · (an-1 ±an-2b +an-3b2 ±an-4b3 +±...+a(±b)n-2 +(±b)n-1) = an ± bn. The mixed terms cancel out themselves.
y(a - by^3 + x) a(b + 3)(b - 5)
AB2
The GCF is ab2
Factor by grouping. x2y - xyb - abx + ab2 The first two can factor out an xy, so xy(x - b) The second two can factor out a -ab, so -ab(x - b) and we have xy(x - b) - ab(x - b) Since what is inside the parentheses is alike, we can be assured that we have factored correctly and now continue to group: ANS: (x - b)(xy - ab)
Let consider the right triangle ABC with hypotenuse AB and heigth AC then base is BC Pythagorean theorem states that AB2=AC2+BC2 so BC2=AB2-AC2 then BC=sqrt(AB2-AC2)
linear
5m