3pq+q+6p+2
5
X squared + 7X + 12?
t(t-1)
-5
5
13X squared + 7X + 12
What about it? Factorise it?
It is: x(x-3) factorized
m(m - 1)
x2 - 41 cannot be factorised.
x^2 - 5x - 6 Since the coefficient of 'x^(2)' is '1' in this case. we look at the constant '6' . So write down all the factors of 6' . They are 1,2,3,&6. From these four number we select two numbers that add/subtract to '- So if we say -6 + 1 = -5 5'. The coefficient of 'x' Since 6 - 1 = 5 & 2 + 3 = 5 We need to think a little deeper. So we look at the mathemetical signs , which in this case are both negative (-). Since the sign in front of the '6' is negative, this means that the signs in the brackets are different. NB If it was a possitive both the signs in brackets would be the same either both (+) or both (-). So to have a '-5' we can say -6 + 1 = -5 So setting up the brackets ( x 6 )(x 1) So the signs will be (x - 6)( x + 1) Done!!!! Hope that helps!!!!
x(x-7)
It is: 3y(2y-3x) when factored