What is the final liquid level of water if the density of aluminum is 2.702 grams per ml and 1.130 ounces of aluminum is dropped into a graduated cylinder containing 15.90 milliliters of water?

Answer 1

First need to convert ounces to grams, so that can used density to calculate volume.

1.13 oz * 28.3495 (g/oz) = 32.034935 g

then divide by density to find volume:

V = 32.034935 g / 2.702 (g/cm3) = 11.8560 cm3

since 1 mL = 1 cm3, the water level will rise by 11.8560 mL

Final level = 15.90 mL + 11.8560 mL = 27.7560 mL = 27.76 mL (2 decimal place)

Answer 2

1.13 oz = 32.034 grams

32.034 grams / 2.702 grams/ml = 11.856 ml

11.856 ml + 15.90 ml = 27.76 ml

Answer 3

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