On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get:
78.4m/s
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
19.6 meters / 64.4 ft
If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.
Acceleration = (change in velocity) / (time for the change)9.8 = (change in velocity) / (2 seconds)9.8 x 2 = change in velocity = 19.6 meters per second .Hint: The mass of the object and the height of the building are there just tothrow you off balance. You don't need either of them to answer the question.
Perhaps you mean terminal velocity. This is the maximum velocity reached by an object falling to the ground when the acceleration due to gravity is matched by the drag resistance of the air through which it is falling.
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
51 seconds.
A apple falling to the ground IS an apple falling to the ground.
In a vacuum (i.e. neglecting air resistance) a falling object would reach a speed of about 124.2 m/s (278 mph) in falling 828 m. However, in an average configuration, a coin would reach terminal velocity at about 18.7 m/s (42 mph) and take approximately 45 seconds to reach the ground from 828 m. Edge on, it could reach 29 m/sec (65 mph) and be on the ground in just 31 seconds. Note that you cannot drop a coin straight down, but would have to throw it outward a distance of at least 15 m (50 feet) to reach the ground. *Base jumpers who jumped from the top of the building (2717 feet) took about 80 seconds to reach the ground including 10 seconds of freefall.
19.6 meters / 64.4 ft
The impact force depends upon the height from which it has fallen (IE- its velocity upon impact), and the duration of impact (determined by the elasticity of the collision). However, the object exerts no force upon the ground *while* falling.
If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
the crate will reach terminal velocity last, but hit the ground frist.
Simply use the expression v = gt g = 9.8 m/s^2 and t given as 4.5 s So velocity with which the penny hits the ground will be 44.1 m/s
An object falling from a tall building would accelerate at a rate of 9.807 m/s2 until it reached terminal velocity, at which point it would not accelerate until it impacted the ground. Its velocity would increase as it fell until reaching terminal velocity, and then 0 when it hit the ground.
A falling snowflake or raindrop does not accelerate as it approaches the ground because their mass doesn't change. The form is not affected throughout the fall so it is already approaching the ground at terminal velocity. Hope this helps.