What is the net force on a dragster with a mass of 900 kg if its acceleration is 32.0 ms squared?

Answer 1

f=m*a

f=800*31

f=24 800 newtons

if applied for 1 second(t) from zero,

distance travelled(s) = 15.5 metres

power =( f*s)/t =( 24800*15.5)/1 = 384 400 watts (about 516 bhp at drive wheels)

Answer 2

mass (m) = 900 kg, acceleration (a) = 32 m/s^2 .

using f=m*a , f = 900 * 32 = 28 800 newtons.

power (watts)= (f * s)/t

say accelerating for 1 second from rest, s=(a*t^2)/2 = 16 metres.

power = (28 800 * 16) / 1 = 448 000 watts ( 601 bhp).

Answer 3

Well, first of all, "miles per second" is a speed, not an acceleration. I'll fix it

and make it an acceleration, in order to go on and find an answer. Call the

acceleration 322 miles per second2 .

322 miles/second2 = 518,208.8 meters/second2

Force = (mass) x (acceleration) = (0.9) x (518,208.8) = 466,388 Newtons (rounded)

That's the same as about 104,844 pounds . . . an awful lot of force, but the

really amazing part is the tires that can hold the track with that kind of torque.

Answer 4

Net force on the dragster is 28,800 newtons or 6,474.5 pound-force.

Answer 5

Net force is 28,800N