the force of tension in the rope, which is delivered to the object to which the opposite end of the rope is attached
That depends on the specific situation. Note that by Newton's Third Law, the force exerted by a wall on a rope is the same as the force exerted by the rope on the wall.
The breaking strength of the rope has to be stated in terms of the "tension" in the rope, and that has to be the 800N quoted here. If the ends of the rope are pulled in oppposite directions with a force of 500N on each end, then the tension in the rope at any point is 1000N, and yes, it will break.
A pulley directs the force in a rope into a new direction.
Tension
the force of tension in the rope, which is delivered to the object to which the opposite end of the rope is attached
That depends on the specific situation. Note that by Newton's Third Law, the force exerted by a wall on a rope is the same as the force exerted by the rope on the wall.
I am not sure what you mean by "a surface that re-directs force" but you could use a pulley to redirect a force from a rope.
The breaking strength of the rope has to be stated in terms of the "tension" in the rope, and that has to be the 800N quoted here. If the ends of the rope are pulled in oppposite directions with a force of 500N on each end, then the tension in the rope at any point is 1000N, and yes, it will break.
A pulley directs the force in a rope into a new direction.
Tension
Rope.
Pulling is the main force in ropes, as you pullthe rope.
A rope and pulley lessen the force needed to pull an item, but it increases the distance that you have to pull it. It also changes the direction that it moves: you pull the rope down, the item goes up.
tension force , contact force, applied force
You get a tension in the chain or rope.
A block of mass M is pulled with a rope on a frictionless surface If a force P is applied at the free end of the rope what will be the force exerted by the rope on the block if the mass of rope is m? Equation#1: Force = mass * acceleration The force P pulls a total mass of (M + m) accelerating both masses at the same rate. Equation #2: P = (M + m) * a Equation #3: a = P ÷ (M + m) At the point where the rope is attached to the block, the block of mass M feels a force making it accelerate at a rate of a = P ÷ (M + m). The force required to make at block of mass M accelerate at a rate of a = P ÷ (M + m) can be determined by equation #4. Equation #4: F of block = mass of block * [P ÷ (M + m)].