Na(BF4) forms so Na+ and (BF4)- are the ions produced
+3 is Boron's overall charge. Boron's ionic charge is +5.
Boron has 3 valence electrons, which allows it to covalently bond to three other atoms. Each of the 3 covalent bonds has a pair of valence electrons, which means boron is sharing a total of six valence electrons in a compound. Boron still prefers an octet. Therefore, Boron can share a fourth bond which means boron will share 8 valence electrons, a full octet. But in this case, boron will have a formal charge: 3 valence - 4 bonds = -1 charge. The structure with 4 covalent bonds is similar to carbon (think CH4), but because boron has one less proton than carbon, boron carries a negative formal charge when boron fills its octet by covalently bondingto 4 atoms.An example of this would be the acid-base reaction:BF3 + diethyl ether (C2H5)2OThe oxygen will use one of its lone pair of electrons to form a covalent bond with boron.This means boron has a minus one formal charge and has 3 bonds (with 3 fluorines)and one bond to oxygen. The oxygen now is sharing one of its lone pairs in a covalentbond, so the oxygen has a plus one formal charge now: 6-3-2=+1.
When bonding, the boron family (group 3) has a +3 charge.
The formula for sulfate is SO4, and has a net charge of -2. Boron has a charge of +3, so the formula for boron sulfate is B2(SO4)3.
Na(BF4) forms so Na+ and (BF4)- are the ions produced
Yes! BF4- is a tetrahedral as it is just a boron with four Florines attached and no lone pairs.
+3 is Boron's overall charge. Boron's ionic charge is +5.
Boron cannot make simple compounds with a filled octet. Though it forms complex ions such as BF4- , BCl4- where it completes the octet.
Boron has 3 valence electrons, which allows it to covalently bond to three other atoms. Each of the 3 covalent bonds has a pair of valence electrons, which means boron is sharing a total of six valence electrons in a compound. Boron still prefers an octet. Therefore, Boron can share a fourth bond which means boron will share 8 valence electrons, a full octet. But in this case, boron will have a formal charge: 3 valence - 4 bonds = -1 charge. The structure with 4 covalent bonds is similar to carbon (think CH4), but because boron has one less proton than carbon, boron carries a negative formal charge when boron fills its octet by covalently bondingto 4 atoms.An example of this would be the acid-base reaction:BF3 + diethyl ether (C2H5)2OThe oxygen will use one of its lone pair of electrons to form a covalent bond with boron.This means boron has a minus one formal charge and has 3 bonds (with 3 fluorines)and one bond to oxygen. The oxygen now is sharing one of its lone pairs in a covalentbond, so the oxygen has a plus one formal charge now: 6-3-2=+1.
Boron trifluoride BF3 reacts with F- ion to form the BF4- ion. BF3 has only 6 electrons around the B atom, is planar, and is a Lewis acid (as it will accept electrons from an electron pair donor such as F-. BF4- is a tetrahedral ion- all four bonds are equivalent.
This just means it has a charge of 1+. The Boron ion can only have a charge of 1+.
When bonding, the boron family (group 3) has a +3 charge.
The formula for sulfate is SO4, and has a net charge of -2. Boron has a charge of +3, so the formula for boron sulfate is B2(SO4)3.
The structure of BF4- is tetrahedral.
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