AgBr2 However, this would be an uncommon compound as silver ions most often occur in the +1 state.
AgBr
AgBr is the chemical formula of silver bromide.
The molecular formula for silver bromide is AgBr.This is a soft and pale-yellow salt which is particularly known for its unusual sensitivity to light.
The equation of the reaction is BaBr2 + 2 AgNO3 -> 2 AgBr + Ba(NO3)2. Therefore, exactly as many bromide ions from barium bromide must be supplied to precipitate any particular number of silver ion from silver nitrate. From the definition of molarity, 100 ml of 52 M solution contains 5.2 moles (preferably called "gram formula units") of silver nitrate. The gram formula unit mass of silver nitrate is 169.87, and each gram formula mass contains equal numbers of silver and of nitrate ions. Therefore, 5.2 gram elemental masses of bromide ions will be required for the precipitation. This amount of bromide ions can be supplied by 5.2/2* or 2.6 gram formula masses of barium bromide, and the gram formula unit mass of barium bromide is 297.14. Multiplying this number by 2.6 shows that 7.7 X 102 grams of barium bromide, to the justified number of significant digits, will be needed.
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.
You can write for two formula units 2 AgBr.
SBr
AgBr
AgBr is the chemical formula of silver bromide.
The molecular formula for silver bromide is AgBr.This is a soft and pale-yellow salt which is particularly known for its unusual sensitivity to light.
The equation of the reaction is BaBr2 + 2 AgNO3 -> 2 AgBr + Ba(NO3)2. Therefore, exactly as many bromide ions from barium bromide must be supplied to precipitate any particular number of silver ion from silver nitrate. From the definition of molarity, 100 ml of 52 M solution contains 5.2 moles (preferably called "gram formula units") of silver nitrate. The gram formula unit mass of silver nitrate is 169.87, and each gram formula mass contains equal numbers of silver and of nitrate ions. Therefore, 5.2 gram elemental masses of bromide ions will be required for the precipitation. This amount of bromide ions can be supplied by 5.2/2* or 2.6 gram formula masses of barium bromide, and the gram formula unit mass of barium bromide is 297.14. Multiplying this number by 2.6 shows that 7.7 X 102 grams of barium bromide, to the justified number of significant digits, will be needed.
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.
AgBr is silver bromide. Ag2Br does not exist. Hg2Br2 is mercury(I) bromide.
the name is cobalt 2 bromide or cobaltous bromide
Mercury(I) bromide formula is Hg2Br2Mercury(II) bromide formula is HgBr2See attached link for more information on mercury bromide.
AgBr is the chemical formula (not symbol) of silver bromide.
Silver bromide (AgBr), a soft, pale-yellow, water insoluble salt