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Period of a pendulum (T) in Seconds is:
T = 2 * PI * (L/g)1/2
L = Length of Pendulum in Meters
g = Acceleration due to gravity = 9.81 m/s2
PI = 3.14
The period is independent of the mass or travel (angle) of the pendulum.
The frequency (f) of a pendulum in Hertz is the inverse of the Period.
f = 1/T
What else can I help you with?
The gravitational acceleration on the surface of Mars is 3.7m s 2 What period Would a 64 meters long pendulum have on Mars?
The period of a pendulum on Mars compared to Earth would be about 1.62 times longer.The period of a pendulum is (among other factors) inversely proportional to the square root of the acceleration due to gravity. The gravity of Mars is 0.38 that of Earth, so the square root of one over 0.38 is 1.62.T ~= 2 pi sqrt (L/g) where theta far less than 1.For larger theta, longer periods are incurred, with various correction factors, but the basic equation remains the same.
House current in the US oscillates how many times in one second?
The general oscilattion rating for a United States household electrical system is 60 times per second. This is know as Hrtz (prnounced Hets). Therefore, home electrical systems in the US run at 60 Hrtz.
In 6 seconds a light flashes once In one hour how many times it will flash?
600, 60(seconds)x60(minutes)=3600(seconds)/6=600
How many million second is in how many days?
There are 86,400 seconds in one day so Amount of days times 86400 and you have got your answer
What period of time is the modern times?
The modern times typically refer to the period from the late 18th century to the present day, characterized by significant industrial, technological, and societal advancements.
A pendulum oscillates 60 times in 6 seconds.Find its time period and frequency?
Frequency=60/6=10Hz Time Period=1/f=1/10
What is a period wave with the frequency of 2.6 Hz?
A period wave with a frequency of 2.6 Hz completes one full cycle (peak to peak or trough to trough) every 0.38 seconds. This means it oscillates 2.6 times in one second.
A pendulum that is 38 cm long will swing how many times in 15 seconds?
12.
How do you find determine the period of the pendulum A pupil obtains the following values for 20 oscillations of a pendulum 12.6s 12.7s 12.5s 12.6s 12.7s Determine the period of pendulum?
First take the average of your times:(12.6 + 12.7 + 12.5 + 12.6 + 12.7) / 5 = 12.62This is your average time for 20 oscillations. The period is the time for one oscillation, and therefore the period is 12.62/20 = 0.631 seconds.A complete oscillation is when the pendulum swings from the start position to the opposite position on the swing and back again. Assuming this is what you counted twenty of, then your pendulum is 10 cm long.If you counted 20 swings to each side, then you really only counted 10 oscillations. This means that your period would be 1.262, and would suggest that your pendulum is 40cm long.
Time period of a pendulum on moon is?
About 40.7% of that on Earth or about 2.46 times slower.
How does frequency affect the pendulum?
The frequency of a pendulum is related to its period, or the time it takes to complete one full swing. The frequency increases as the pendulum swings faster and the period decreases. In essence, an increase in frequency means the pendulum is swinging more times per unit of time.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
If the length of a simple pendulum is doubled what will be the change in its time period?
ts period will become sqrt(2) times as long.
What changes can you make to affect the pendulum so that it can swing more or less swings in 15 seconds?
To make the pendulum swing more times in 15 seconds, you can increase its length or increase the angle of release. To make it swing less in 15 seconds, you can decrease the length or reduce the angle of release. Additionally, reducing air resistance by swinging in a vacuum can also affect the number of swings in 15 seconds.
How many times does a 32 inch pendulum swing in one minute?
Period ( left swing + right swing) of a simple pendulum = 2*pi * sqrt (L/g) in seconds. g = 32.2 feet per second2 L = 32 inches = 2.66667 feet Period = 2*pi * sqrt ( 2.66667ft/32.2) = 2*pi * 0.287777 = 1.808158 seconds for one period (two swings). Periods in one minute = 60 sec / 1.808158 sec = 33.183 periods in one minute. Times 2 = 66.366 swings in one minute.
How does the length of a string affect the number Of times a pendulum will swing back and fourth in 10 seconds?
The length of a pendulum affects its period of oscillation, which is the time taken for one complete swing back and forth. A longer pendulum will have a longer period and therefore fewer swings in a given time period, like 10 seconds. Conversely, a shorter pendulum will have a shorter period and more swings in the same time frame.
If length of simple pendulem increases constantly during osscillation then what is effct on time period?
If the length of a simple pendulum increases constantly during oscillation, the time period of the pendulum will also increase. This is because the time period of a simple pendulum is directly proportional to the square root of its length. Therefore, as the length increases, the time period will also increase.
