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Q: What is the frequency of oscillation of a simple pendulum which makes 50 oscillations in 24.4 seconds?

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This sounds like a homework question, so rather than doing your homework for you, I'll explain how to find the answer for yourself.The period and the frequency are very easy to find from the information provided. First, remember the definitions of period and frequency:Period is the amount of time per oscillation.Frequency is the number of oscillations per unit time.When you see the word "per" in these definitions, you should think division, because that is how you find the answer. When we say period is time per oscillation, this means time divided by oscillations. So your period is obtained by dividing the amount of time (in seconds) by the number of oscillations in that time. The units will make sense this way too: time divided by oscillations will give you a number that means seconds PER oscillation, which is what period is!Similarly, frequency is oscillations per time, so take the number of oscillations and divide it by the number of seconds it took. Your units will be oscillations per second, which makes sense for a measure of frequency.

The frequency of a pendulum is 1 divided by (the number of seconds to make one complete swing)

In order to find the frequency of an oscilloscope trace, you must first find the period, which is the time it takes for one oscillation, which can be found by measuring the amount of time from one peak our trough to the next. The frequency is the number of oscillations per second, and can be found by dividing 1 by the period in seconds.

mhz ( megahertz) is a unit of frequency while seconds is a unit of time ,so normally they can't be converted to one another.But if you want to convert mhz to seconds (as in case of pendulum to find out the time period of the pendulum if frequency is provided) multiply the frequency by 106 (to convert mega hertz int hertz) and then take out the reciprocal of the quantity(as frequency=1/time period)

That would be 1/3 SPS (swings per second)

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Time period per oscillation=32/ 20=1.6 sec per oscillation.

This sounds like a homework question, so rather than doing your homework for you, I'll explain how to find the answer for yourself.The period and the frequency are very easy to find from the information provided. First, remember the definitions of period and frequency:Period is the amount of time per oscillation.Frequency is the number of oscillations per unit time.When you see the word "per" in these definitions, you should think division, because that is how you find the answer. When we say period is time per oscillation, this means time divided by oscillations. So your period is obtained by dividing the amount of time (in seconds) by the number of oscillations in that time. The units will make sense this way too: time divided by oscillations will give you a number that means seconds PER oscillation, which is what period is!Similarly, frequency is oscillations per time, so take the number of oscillations and divide it by the number of seconds it took. Your units will be oscillations per second, which makes sense for a measure of frequency.

The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.

The frequency of a pendulum is 1 divided by (the number of seconds to make one complete swing)

In order to find the frequency of an oscilloscope trace, you must first find the period, which is the time it takes for one oscillation, which can be found by measuring the amount of time from one peak our trough to the next. The frequency is the number of oscillations per second, and can be found by dividing 1 by the period in seconds.

The relationship to be kept in mind is that the time period, which is the time take for one complete oscillation, is the reciprocal of frequency (the number of oscillations completed in one second). That is, T = 1/f where Period T, is measured in seconds Frequency f, is measured in Hertz. In your specific case, if f = 10 Hz, T = 0.1 s.

1

Period of a pendulum (T) in Seconds is: T = 2 * PI * (L/g)1/2 L = Length of Pendulum in Meters g = Acceleration due to gravity = 9.81 m/s2 PI = 3.14 The period is independent of the mass or travel (angle) of the pendulum. The frequency (f) of a pendulum in Hertz is the inverse of the Period. f = 1/T

mhz ( megahertz) is a unit of frequency while seconds is a unit of time ,so normally they can't be converted to one another.But if you want to convert mhz to seconds (as in case of pendulum to find out the time period of the pendulum if frequency is provided) multiply the frequency by 106 (to convert mega hertz int hertz) and then take out the reciprocal of the quantity(as frequency=1/time period)

1/4 Hertz or 1.4 per second.

The frequency is 300/30 = 10 Hz The time period is 30/300 = 0.10 seconds

That would be 1/3 SPS (swings per second)