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It is the event that one of the two coins lands showing tails and the other shows heads.

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0The probability is 50-50.

At least two heads with two coins? You can't get more.There are 4 different outcomes:tail-tail, head-tail, tail-head and head-head.You can use one out of four - which gives us the probability 1/4 = 0.25 = 25%

Three coins can come up in (2 x 2 x 2) = 8 different ways.One tail can come up in 3 different ways . . . one for each coin.The probability of one tail is (3/8) = 0.375 = 37.5%

the probability of getting one head and one tail on three flips of a coin is 1/9

75%. There are 3 possible ways of getting at least one tail from 2 tosses from a coin:Tail & Tail orHead & Tail orTail & HeadEach of these individual outcomes has a probability of 25% (e.g. the probability of getting a tail and then another tail is 25%). Adding the possible outcomes together gives you a total of 75%.

The probability of getting at least one tail in a flip of six coins is the same as the probability of not getting all heads, which is 1 - (0.56), or 0.984375.

pr(at most one T) = 1 - pr(not two tails) = 1 - 1/2*1/2 = 1 - 1/4 = 3/4

With 4 coins you have 24 (16) possibilities. If we wanted a specific coin to land 'tails' while the others landed 'heads' we would have one possibilty out of 16. Since we don't care which of the coins lands 'tails,' we have four chances in 16 or a 25 percent chance.

n(S)=8 let A be the event that more than one tail appears n(A)=4 so,P(A)=4\8=0.5

The theoretical probability of HT or TH when two coins are tossed is 1/2 . (All possible outcomes are HH,TT,HT,TH). This means that when we run the experiment repeatedly we expect to get the desired result 1/2 of the time. Since you intend to toss the coins 40 times, 20 are expected.

There are 4 events: 3 heads, 2 heads 1 tail, 1 head 2 tails, and 3 tails.

Number of possible outcomes of one coin = 2Number of possible outcomes of six coins = 2 x 2 x 2 x 2 x 2 x 2 = 64Number of possible outcomes with six heads = 1Probability of six heads = 1/64Probability of not six heads = at least one tails = 63/64 = 98.4375%

there can be only three combo's ------ head n tail,,,,,,,, tail n tail,,,,,,,,,,,,,, head n head

No, the possible results of two coin flips are; HH HT TH TT The probability of getting exactly one tail is 1/2 or 50%.

Since the coin only has two sides, the probability of getting either heads or tails in any one toss is 1 in 2, or 50%. 50 precent chance. Everytime you toss it, 50 percent.

In three tosses there can be four possible outcomes: three heads, three tails, two heads and one tail, and one head and two tails. ^^^That is wrongA coin is tossed N times. There are 2 possibilities when you toss a coin: heads and tails.So the formula is 2^N (thats to the N power)A coin tossed 3 times has 2^3=8 possible outcomes:head head headhead head tailhead tail headtail head headtail tail headhead tail tailtail head tailtail tail tailThere they are!

http://wiki.answers.com/Q/If_you_Flip_four_coins_at_once_what_is_probability_of_2_head_and_3_tail" The probability of flipping four coins and getting 2 heads and 3 tails is ZERO 2 heads and 3 tails requires flipping FIVE coins.

25% or 0.25 Probability of one tail is 0.50. Since two tails are independent events, the probability is 0.5 x 0.5 = 0.25

When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban

lets get some facts odds of head on 1 coin 50% or evens odds of no head 50% or evens the possible results vary from 1 coin to 2 coins. 1 coin has 2 results heads or tails 2 coins have 4 results. heads heads, tails tails, tails heads, heads tails. each outcome has a probability of 25%. for the question we remove the heads and tail probability and we have 2 outcomes with heads and one without. so 2 to 1 chance or 33.3333 recuring chance.

The answer in the back of the book says that it is: TT, TH, H1, H2 H3, H4, H5, H6= 8 possibilities. But I don't understand what that means or how the answer was found. Help?

A coments tail forms by getting closer to the sun.

First work out the probability of the first two coins being heads and then the last being tails. This is 1/2 x 1/2 x 1/2 which is 1/8 The next step is to find out how many different orders the coins can come in. In this case there are 3 possible orders (HHT, HTH, and THH). Multiply this by the above probability and you get 3/8. Therefore the probability of getting two heads and one tail is 3/8

The theoretical probability of getting one head and one tail is 50%

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