910
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
91
46
this is a guess and check problem. answers is 1009. 999 - 10 = 989 lets try one less (998) 998 -9(1 digit) is not possible, lets try one more (1000) 1000(4 digit) - 11 is not possible so only possible solution is (999,10) Answers is 999+10 = 1009
There are 30,240 different 5-digit numbers. Math: 10*9*8*7*6 1st digit has 10 possible choices (0-9) 2nd digit has 9 possible choices (one of the digits was used in the 1st digit) 3rd digit has 8 possible choices 4th digit has 7 possible choices 5th digit has 6 possible choices
All nines 9,999,999,999
Guessing 10 000. The zeros count as a digit. The greatest possible is 99 999. =)
i'll... say both?highest: 99+99+99=297lowest: 10+10+10=30
There are 6 solutions in all.The middle digit must be 0 , 2 or 4.If the middle digit is 0, then the first two digits must sum to 3. There are three possible solutions: 12, 21 and 30.If the middle digit is 2, then the first two digits must sum to 2. There are two possible solutions: 11 and 20.If the middle digit is 4, then the first two digits must sum to 1. There is one possible solutions: 10.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
2
1,000,009
10 + 15 = 25. the tens digit of 25 is 2
91
46
Smallest 2 digit number is 10. 10 + 99 = 109
The smallest is 10 and the greatest is 99.