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Carbon is SP3 hubridized in it.Hydrogen has same hybridization

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11y ago

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The process of hybridisation in carbon?

carbon can have either sp3 ,sp2 or sp1 hybridised orbital depending upon the type of hybridisation hybridisation influences the bond and bond therapy (strength) in the organic compounds


Did carbon atom undergoes hybridisation to form carbon dioxide?

yes


What is the elements of CH4?

There are two types of elements.They are carbon and hydrogen


What is the chemical formula for methane molecule?

Molecular formula: CH4 Structural formula: . H H C H . H CH4 (1 carbon and 4 hydrogen) it is NOT ch4 it is CH4; 4 being a subscript indicating 4 hydrogen atoms bonded into a single carbon atom


What is the weight percent of carbon in CH4?

Carbon has a atomic mass of 12.So its percentage is 75%


Is ch4 orgac or inorganic?

CH4 is organic compound.It contains Carbon and Hydrogen


What is a composition of a diamond?

It is pure (elemental) Carbon (in crystallic tetraedical sp3-hybridisation)


What is the chemical compound name of CH4 not Methane the chemical name?

The chemical compound name for CH4 is carbon tetrahydride.


Name the elements in this compound CH4?

The compound CH4 contains one carbon atom and four hydrogen atoms.


Which of the following compounds is carbon tetrahydride CH4 C4H CaH or CaH4?

CH4. Tetra means 4. Hydride means hydrogen. 4 hydrogen+carbon.


Which is a compound that contains carbon Ca NaCl C CH4?

CH4 (methane) is the compound that contains carbon. Calcium (Ca) and sodium chloride (NaCl) do not contain carbon.


Why it is necessory to assume sp3 hybridization in CH4?

In valence bond theory it is assumed the four electron pair bonds reside tetrahedrally about the carbon giving rise to the terahedral shape of the molecule. sp3 hybridisation is "necessary", it replaces the s , px, py and pz orbitals with four orbitals of identical energy (degenerate) with lobes pointing to corners of a tetrahedron- the 4 electrons are then promoted to these orbitals - the hybridisation energy.