The integral of cosine cubed is sinx- 1/3 sin cubed x + c
because sine & cosine functions are periodic.
This is a nonsense question. Millimeters are a unit of length and the centimeter cubed is a unit of volume. It is like asking how many kilograms are there in a mile. If however you mean, how many millimeter cubed are there in a centimeter cubed then the answer is 1000 10 x 10 x10
sin integral is -cos This is so because the derivative of cos x = -sin x
There is one centimetre cubed in a millilitre. A centimetre cubed is the same thing as a millilitre.
Integral Proteins.
It is cosine*cosine*cosine.
-cosine x
∫ cos(x) dx = -sin(x) + C
looks like the exponents did not show up, in the first it should be 4 cosine cubed x - 3cosx and the sin 3x should be 3sinx - 4sine cubed x
∫ cos(x) dx = sin(x) + CC is the constant of integration.
half range cosine series or sine series is noting but it consderingonly cosine or sine terms in the genralexpansion of fourierseriesfor examplehalf range cosine seriesf(x)=a1/2+sigma n=0to1 an cosnxwhere an=2/c *integral under limits f(x)cosnxand sine series is vice versa
∫ cosh(x) dx = sinh(x) + C C is the constant of integration.
∫ 1/cos2(x) dx = tan(x) + C C is the constant of integration.
∫ 1/cosh2(x) dx = tanh(x) + C C is the constant of integration.
(ex)3=e3x, so int[(ex)3dx]=int[e3xdx]=e3x/3 the integral ex^3 involves a complex function useful only to integrations such as this known as the exponential integral, or En(x). The integral is:-(1/3)x*E2/3(-x3). To solve this integral, and for more information on the exponential integral, go to http://integrals.wolfram.com/index.jsp?expr=e^(x^3)&random=false
I will assume that this is sopposed to be integrated with respect to x. To make this problem easier, imagine that the integrand is x raised to the negative 3. The integral is 1/(-2x-2) plus some constant c.
∫ sin(x)/cos2(x) dx = sec(x) + C C is the constant of integration.