uv max of pregabalin are following:
1.in water 276nm
2.in methanol 210nm
The reported UV lambda max of Vildagliptin drug is 254 nm.
Wavelength lambda and frequency f are connected by the speed c of the medium. c can be air = 343 m/s at 20 degrees celsius or water at 0 dgrees = 1450 m/s. c can be light waves or electromagnetic waves = 299 792 458 m/s. The formulas are: c = lambda x f f = c / lambda lambda = c / f
We got the formula: speed of medium c = frequency f times wavelength lambda. f = c / lambda lambda = c / f c = 343 m/s at 20°C or 68°F in air. For f = 350 Hz lambda = 343 / 350 = 0.98 meters
EM waves travel at the speed of light in a vacuum. c=f*lambda where c is the speed of light, f is the frequency of the way and lambda is the wavelength. Lambda= c/f = (3x108 m/s)/3x1010 s-1) = 1x10-2 m or 1 cm
platina pi, lambda, alpha, tau, iota, nu, alpha
The lambda max is 510 nm.
The reported UV lambda max of Vildagliptin drug is 254 nm.
257 nm
intrinsic property
495
251 NM
236nm
520 nm
254 nm
The base value of this structure is 253 nm. There are 4 alkyl substituents which add a value of 20 (4x5 nm). So the lambda max of this structure is 273 nm.
using uv-visible spectrophotometer concentration vs absorbance is plotted and the maximum absorbance of the drug is lambda max of the drug. then after it will decrease. still if needed clarification, refer beer lambert"s law
differnce between fluoresence and phosphoresence