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Q: What is the largest 5 digits number that is both divisible by 6 and 9?
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What largest 3 - digit number divisible by both 6 and 9?

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.


What is the largest 2 digit number that is both prime and has prime numbers for both of its digits?

73 is the largest 2 digit number that is both prime and has prime numbers for both of its digits.


What is the largest two-digit number that is prime and has prime numbers for both of its digits?

73 is the largest two-digit number that is prime and has prime numbers for both of its digits.


What is the smallest two digit number that is divisible by both the sum and the product of its digits?

12


What is a 2 digit number the sum of your digits is 11 the number is divisible by both 4 and 7 the number is?

56


What is the largest 5-digit number that is divisible by both 24 and 50?

99,600 is the largest 5-digit number that meets both requirements.


You are a 2 digit number The sum of your digits is 11 you are divisible by both 4 and 7 you are?

56


Is 5232 divisible by 6?

Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.


How do you know that a number is divisible by 15?

A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3


What is the largest 5-digit number is divisible by both 2 and 3?

99,996


What is the largest three digit number divisible by both 3 and 10?

990.


Is 5278 divisible by3?

Add up the digits---5+2+7+8 22 which is NOT a multiple of 3 so it is NOT divisible by 3. == Here is a list of the divisibility rules: 2 If the last digit is even, the number is divisible by 2. 3 If the sum of the digits is divisible by 3, the number is also. 4 If the last two digits form a number divisible by 4, the number is also. 5 If the last digit is a 5 or a 0, the number is divisible by 5. 6 If the number is divisible by both 3 and 2, it is also divisible by 6. 7Take the last digit, double it, and subtract it from the rest of the number;if the answer is divisible by 7 (including 0), then the number is also. 8If the last three digits form a number divisible by 8,then so is the whole number. 9 If the sum of the digits is divisible by 9, the number is also. 10 If the number ends in 0, it is divisible by 10. 11 Alternately add and subtract the digits from left to right. (You can think of the first digit as being 'added' to zero.)If the result (including 0) is divisible by 11, the number is also.Example: to see whether 365167484 is divisible by 11, start by subtracting:[0+]3-6+5-1+6-7+4-8+4 = 0; therefore 365167484 is divisible by 11. 12 If the number is divisible by both 3 and 4, it is also divisible by 12. 13Delete the last digit from the number, then subtract 9 times the deleteddigit from the remaining number. If what is left is divisible by 13,then so is the original number