Using Pythagoras; theorem it is 12 Times Square root of 2 which is about 17 cm rounded to the nearest integer
Using Pythagoras' theorem: 8 times the square root of 2 which is about 11,3137085 cm
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
Each side = sqrt (182 / 2) = sqrt (162) = 12.72792 metres
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.
The perimeter of this square is 45.25 cm
Using Pythagoras' theorem: 8 times the square root of 2 which is about 11,3137085 cm
The square's diagonal is 11.314 cm
The length of the diagonal of a square whose side lengths are 7 square root 2 (9.89949494) is: 14 units.
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
4
Using Pythagoras's theorem, you will find that the diagonal is sqrt(2) = 1.4142 cm (approx),
a≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm
There is no such thing as a square whose length and width are different.
A square with a side length of 6 inches has an area of 36 square inches.
The diagonal of a 46' x 46' square is 65.05 feet.
Using Pythagoras' theorem the length of the diagonal is 20 feet
The diagonal of a square is usually found using Pythagoras's theorem, a2 + b2 = c2. Since this is a square, a = b; thus: c2 = 2s2, where s is the side length and c is the diagonal. s = square root(c2/2) = square root(625/2) = square root(312.5) = 17.8in The dimensions of a square whose diagonal is 25inches is 17.8in x 17.8in (rounded to the nearest tenth)