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Answered 2018-01-13 13:07:28

The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1

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Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..




Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.



That's the equation of a circle with its center at the origin and a radius of 8.


10 Both the x-intercept (y=0) and the y-intercept (x=0) have a length of 10 units.


If x^2 plus y^2 = 169 then the center of the circle is at (0, 0) and its radius is the square root of 169 which is 13



The circles are concentric with centre (0,0). The radius of the outer circle is sqrt(72), that of the inner circle is sqrt(18). By Pythagoras, the length of the semichord is sqrt(72 - 18) = sqrt(54) units. Therefore the chord is 2*sqrt(54) = 6*sqrt(6) = 14.679 units (approx).


A circle, centre (0,0), radius = 5


Draw a circle with its center at the origin and a radius of 3.


The graph of that equation is a circle, centered at the origin, with radius = 2 .



A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6



5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.


It is the equation of a circle with radius of 6 and its center at the origin.


Centre of circle: (4, -2) Slope of tangent: 1 Slope of radius: -1 Radius equation: y--2 = -1(x-4) => y = -x+2


I think you have missed out an equals sign. If you mean x2 + y2 = 16, then the radius is 4.



10. Equation of circle is x2 + y2 = r2. Consider: when x = 0 y2 must = 100 so y = 10 which describes a circle centre the origin, radius 10. Similarly when x = 10 y must be 0.


The graph is a circle with a radius of 6, centered at the origin.


x2 + y2 = 144 = radius squared radius = sqrt (144) = 12 diameter = 2 x radius = 24



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