Want this question answered?
To improve magnification. Also so that we can get a real and inverted image
A stamp collector uses a converging lens with focal length 25 cm to view a stamp 13 cm in front of the lens.
It is called the focal length. It is equal to 1/2 times r, and is positive on concave mirrors and negative on convex mirrors.
The focal length of a lens is the distance from the principal foci to the center of the lens.
The focal point is the point where light converges after it passes through a concave lens. The focal length is the distance of the focal point to the lens. Same for a convex lens, except that the focal point is the imaginary point from where light deflected from lens seems to have emerged.
A telescope consists of two lenses. 1) The main lens which collects the light ( it is relatively bigger that eyepiece). 2) Eye piece , through which we see. Magnification of a telescope depends on the focal length of the eye piece and the main lens. Magnification = Focal length of the main lens / Focal length of the eyepiece . For example : If the focal length of the main lens is 12 units and the focal length of the eyepiece is 2 units , then the magnification will be 12/2 = 6.When the focal length of the main lens is constant , the focal length of the eyepiece is inversely proportional to the magnification.
Divide the focal length of the objective lens by the focal length of the eyepiece.
A lens of short focal length has a greater power (than a lens of large focal length)
The focal length of the main optical system and the focal length of the lens forming the image.
A parfocal lens is a lens that stays in focus when magnification/focal length is changed. There is inevitably some amount of focus error, but small enough to be considered insignificant.
A tele-conversion lens attaches to a digital camera to increase the lens magnification. It enhances the telephoto effect and adds focal length.
The magnification (MA) equals the focal length of the objective lens (fo) divided by the focal length of the eyepiece (fe), which is this: MA = fo / fe = 10 feet / .25 inches = 120 inches / .25 inches = 480 A link to the Wikipedia article on magnification is included.
That's 80 power.
The longer the focal length the greater the zoom or magnification. If this was not your question go to the discussion page and elaborate. If you can't find the discussion page elaborate here.
To improve magnification. Also so that we can get a real and inverted image
Step 1 Write down the maximum focal length of the lens for which you want to find the magnification. For instance, a 70-250 mm lens will have a maximum focal length of 250mm. A prime lens will have only one value listed, and this value should be considered the maximum focal length. Step 2 Multiply this value by 1.6 if you are attaching the lens to a digital camera. Most digital cameras have a 1.6x "crop factor", which means that the outside edges of a scene will be cropped because they do not physically fit on the sensor, making the effective focal length 1.6 times greater than it would be on a film camera. For a 250mm lens, the effective focal length would be 400 (250 times 1.6). Step 3 Divide the effective focal length by 100. An easier way to do this is to move the decimal point two spaces to the left. The effective focal length of a 250mm lens on a digital camera is 400mm, so divide 400 by 100 to arrive at four. Step 4 Multiply this value by two to find the magnification of the lens in terms of viewfinder magnification used in binoculars or telescopes. So a 250mm lens would have an 8x magnification (400 divided by 100 multiplied by two) on a digital camera.
A stamp collector uses a converging lens with focal length 25 cm to view a stamp 13 cm in front of the lens.