mass in gram = number of moles x atomic weight
So
mass of 5.01 mol of Xe = 5.01 x 131.29 = 657.76 grams
The molar mass of xenon hexafluoride (XeF6) is 245.28 g/mol.
The formula mass of xenon tetrafluoride (XeF4) can be calculated by summing the atomic masses of each element in the compound. The atomic mass of xenon (Xe) is 131.29 g/mol, and the atomic mass of fluorine (F) is 18.998 g/mol. Therefore, the formula mass of XeF4 is 207.29 g/mol.
H2O's molar mass is 18 g/mol.
First, calculate the molar mass of xenon hexafluoride (XeF6). Xenon has a molar mass of 131.29 g/mol and each fluorine atom has a molar mass of 19.00 g/mol. Therefore, the molar mass of XeF6 is 131.29 + (6 * 19.00) = 209.29 g/mol. Next, calculate the number of moles in 3.2 grams of XeF6 by dividing the given mass by the molar mass: 3.2 g / 209.29 g/mol ≈ 0.0153 moles of XeF6. This means that there are about 0.0153 moles of fluorine atoms in 3.2 grams of xenon hexafluoride.
To find the mass of 44.0 mol of Xe (xenon), you need to multiply the number of moles by the molar mass of Xe, which is approximately 131.3 g/mol. So, 44.0 mol Xe * 131.3 g/mol = 5777.2 g of Xe.
The mass in grams of 5,01 mol of xenon is 657,778 g.
The molar mass of xenon hexafluoride (XeF6) is 245.28 g/mol.
The formula mass of xenon tetrafluoride (XeF4) can be calculated by summing the atomic masses of each element in the compound. The atomic mass of xenon (Xe) is 131.29 g/mol, and the atomic mass of fluorine (F) is 18.998 g/mol. Therefore, the formula mass of XeF4 is 207.29 g/mol.
H2O's molar mass is 18 g/mol.
I assume you mean the molecular mass. Its molecular mass is 131.293g/mol
First, calculate the molar mass of xenon hexafluoride (XeF6). Xenon has a molar mass of 131.29 g/mol and each fluorine atom has a molar mass of 19.00 g/mol. Therefore, the molar mass of XeF6 is 131.29 + (6 * 19.00) = 209.29 g/mol. Next, calculate the number of moles in 3.2 grams of XeF6 by dividing the given mass by the molar mass: 3.2 g / 209.29 g/mol ≈ 0.0153 moles of XeF6. This means that there are about 0.0153 moles of fluorine atoms in 3.2 grams of xenon hexafluoride.
To find the mass of 44.0 mol of Xe (xenon), you need to multiply the number of moles by the molar mass of Xe, which is approximately 131.3 g/mol. So, 44.0 mol Xe * 131.3 g/mol = 5777.2 g of Xe.
The molar mass of XeF4 (xenon tetrafluoride) is approximately 207.29 grams/mol. This value is calculated by adding up the atomic weights of each atom in the compound (131.29 g/mol for xenon and 18.998 g/mol for fluorine, multiplied by 4).
To find the percent mass of oxygen in xenon trioxide (XeO3), we first calculate the molar mass of XeO3. Xenon has a molar mass of 131.3 g/mol, and oxygen has a molar mass of 16.00 g/mol. So the molar mass of XeO3 is 131.3 + 3(16.00) = 179.3 g/mol. The mass of oxygen in XeO3 is 3(16.00) = 48.00 g. Therefore, the percent mass of oxygen in XeO3 is (48.00 g / 179.3 g) x 100% ≈ 26.73%.
63.01 g mol-1
The gram formula mass of acetic acid (CH3COOH) is approximately 60.05 g/mol.
The gram formula for potassium sulfite (K2SO3) is 158.27 g/mol.