Is there more to this question? You're asking for numbers for two different ideas without sufficient information. A mole [mol] is the molecular wgt in grams of a given substance which you haven't specified unless I misunderstand your question.
Learn to ask questions with scrupulous accuracy. Often then, the answer will crystallize for you from that alone---ie; a properly framed question.
Octane or C8H18, has a molar mass of 114.23 grams per mole. 5.90 moles of the substance has a mass of 674 grams.
The molar weight of C8H18 is 114 g/mol. So you can find the mass by multiplying molar weight by the number of moles. 5,90x114=672,6 grams.
mw (molecular weight) of C =12
mw of H = 1
12(8) +12(1)=108 g
108g = 1 mol
so 5.9 moles = 108 (5.9)= 637.2 g
5.9moles of C8H18=637.2 g
C: 8x12=96
H: 1x18=18
96+18=114
118x5.9= 673g
The mass of 5,9 moles of octane is 673,957 g.
It is 674g.
The autoignition temperature is 590 oC.
590-650 degrees Celsius. Embacy.
310 degrees Fahrenheit = 154.4 degrees Celsius.
The autoignition temperature is 590 oC.
2253kJ/mol Calculation below Ca(2+) + 2 Cl | 242 | Ca(2+) + Cl2 | | | 348.7 * 2 | 1145 2 Cl(-) + Ca(2+) | | Ca(+) + Cl2 | | 590 | Ca(g) + Cl2(g) | 2253 | 178 | Ca(s) + Cl2(g) | | 795 | CaCl2(s)------------
This cannot be sensibly answered. Milliliters (mL or ml) is a measure of volume, grams is a measure of weight or mass.
Expressed in grams, this is equal to 870 + 590 = 1460 grams. Expressed in kilograms, this is equal to 1.46 kilograms.
590 g = about 1.3 pounds
590 ml of water weigh 590 g. anything other then water will depend on density and the mass you can calculate from the weight
There are 1000 milligrams in one gram. Therefore, 590 milligrams is equal to 590/1000 = 0.59 grams. Adding this to 757 grams gives 757 + 0.59 = 757.59 grams.
590
1 mole of helium (or 4 g or 0.004 kg) has 6 x 1023 atoms. So, 590 kg of helium will have 8.9 x 1028 atoms
590
32% of 590= 32% * 590= 0.32 * 590= 188.8
580
1 lb = 453.6 grams1.20 lb x 453.6 grams/ 1 lb = 544.32 grams
600 would be nearest hundred 590 would be nearest ten