1 mole H2O = 18.015g H2O = 6.022 x 1023 molecules H2O
1.5 x 1023 molecules H2O x 18.015g H2O/6.022 x 1023 molecules H2O = 4.5g H2O
Since the molecular mass of water is about 18 and the molecular mass of C12H22O11 is about 342, it takes considerably more molecules of water to make up 9 g than molecules of C12H22O11 to get the same mass.
1. Find the molar mass of the hydrate (Calcium Chloride Dihydrate).Find the molar mass of water and the anhydrate (anhydrate + water = hydrate); add the molar mass values of each to find the molar mass of the hydrate.Molar Mass CaCl2: 110.98g+ Molar Mass H2O: 36.04g*Molar Mass CaCl2 * 2H2O: 147.01gFinding Molar Mass# atoms element A * atomic mass element A = Mass A# atoms element B * atomic mass element B = Mass B... etc.Add up all the mass values and you have the value for molar mass. Do this for both the anhydrate and the water molecules. Add these values together to find the molar mass of the hydrate.Molar Mass Anhydrate + Molar Mass Water Molecules* = Molar Mass Hydrate* Tip: the molar mass of water for all hydrate calculations is 18.02g x number of water molecules. This number may be useful to remember on the day of the test or while doing practice problems.*2. Calculate the percentage of water in hydrate.Divide the molar mass of water by the molar mass of the hydrate, and multiply result by 100%.36.04g147.01g x 100%Percent water in hydrate is 24.52%.
Yes. For example water molecules (2 hydrogen connected to 1 oxygen atom) have a bent shape.
500 trillion = 500x10^12 molecules = 5x10^14 molecules5x10^14 molecules x 1 mole/6.02x10^23 molecules x 18 gram/mole = 15x 10^-9 grams = 1.5x10^-8 gThis is obviously a very small amount of water.
Because the water molecules are spread over a larger volume in a vapour than they are in a solid.
no it has more
You can change the mass of water in two ways: increase or decrease the amount of water or change the isotopic composition of the molecules of water. The first will have no effect on the mass of 1 cc of water. The second will. If you replace the hydrogen atoms in the "normal" water molecules with deuterium atoms you will increase the density (mass/cc) of the water.
Mass is mass. It is constant. Changing water from liquid to gas does not change the mass, it only changes the density, which is mass per volume. Look at it another way - in gaseous form, the same mass of water has the same number of molecules of water - but those molecules are simply further apart.
Since the molecular mass of water is about 18 and the molecular mass of C12H22O11 is about 342, it takes considerably more molecules of water to make up 9 g than molecules of C12H22O11 to get the same mass.
There is no way that mass can be created or destroyed. Here is an informal way to consider the situation. When you evaporate the water, the distance between the molecules increases. But no new molecules are created (or destroyed). Well, the mass is not simply the total number of molecules - but this gives you an idea how this situation works.
The mass of the water The number of molecules
NO. Water has a density greater than gasoline, but gasoline, octane anyway, has a greater molecular mass than water molecules.
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Mass is just "the amount of stuff there is". We can measure it in kg. If I have 4kg ice and 4kg water, then the answer is "no", but I could just as easily have 4kg of ice and 5kg water, in which case the answer is "yes". If you mean "does freezing water make it heavier?", then the answer is no - 4kg water makes 4kg ice, and they will weigh the same. However, ice has a greater volume than water*, so freezing water will make it expand. *This is not true for every liquid/solid combo.
because water molecules attach to dust particle. when tiny mass of water has formed on a dust particle, other molecules will join the liquid mass.
Avogadro's Number is defined as the number of molecules in one gram atomic molecular mass of a substance and is known to have the approximate value of 6.022 X 1023. The gram molecular mass of water, with formula H2O, is 18.01528. Therefore, the number of water molecules in 1.805 grams of water is: (1.805/18.01528)(6.022)(1023) or 6.034 X 1022 molecules, to the justified number of significant digits.
The mass is 74,7 mg.