What is the volume for a mass of 9.5 grams?

Answer 1

It depends on the density of the material. You must know, or be able to determine, the density of what you're measuring in order to determine the volume occupied by 9.5 grams of it.

Density = mass divided by volume. So, volume = mass divided by density.

For example, the volume of 9.5 grams of gold or lead is less than the volume of 9.5 grams of aluminum -- because gold and lead both have a higher density than aluminum does. (Logical, since a bucket filled with lead is a lot harder to lift than a bucket filled with aluminum.)

For reference, the volume of 9.5 grams of water (at a standard temperature, pressure, etc.) is 9.5 ml. or 9.5 cc. (1 ml. or millilitre equals 1 cc. or cubic centimetre; both being the volume of a cube with sides measuring one centimetre.)

The volume of 9.5 grams of any solid, liquid, or gas, is inversely proportional to the density, and can be compared to the volume and density of water. (For example, 9.5 grams of a material that's 9.5 times denser than water would occupy a volume of 1 ml. or 1 cc.)

For a material of unknown density, you can determine its density by submerging a known mass of it in water, and measuring the volume (hence, the mass) of water it displaces. That's known as Archimedes Principle. Archimedes wanted to know if an object was pure gold (with a known density), or if it was gold mixed with a cheaper metal (with an unknown density). That's why Archimedes was motivated to be able to determine the density of an unknown material.

For any material of known density, just look up its density, then calculate its volume using the formula above (volume = mass divided by density).

Answer 2

Somehow your data doesn't add up.

The mass difference would be 195 - 125 = 70 grams.

1 ml of water weighs roughly 1 gram, so you would expect 70 ml of water to be filled into the beaker.

Your water is either contaminated, extremely heavy or its a trick question.

Answer 3

The volume of the beaker is 50 mL and water occupy 9 mL.