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I am assuming you mean the density is 4.0 g/ cm3 and the displaced H20 is 3.0 cm3 (3 mls when converted to cm3). Look at the units that should tell you how to solve the problem. Your answer must in g (mass), thus you take 4.0 g/cm3 times 3.0 cm3. Units are treated like numbers, for example 3 times 1/3 equals 1 - both 3's cancel leaving only 1 time 1 which equals 1. In this case you have 4 g/cm3 times 3.0 cm3, cm3's cancel leaving only g as your unit at the end. The rest is for you to solve! Enjoy your problem. I am assuming you mean the density is 4.0 g/ cm3 and the displaced H20 is 3.0 cm3 (3 mls when converted to cm3). Look at the units that should tell you how to solve the problem. Your answer must in g (mass), thus you take 4.0 g/cm3 times 3.0 cm3. Units are treated like numbers, for example 3 times 1/3 equals 1 - both 3's cancel leaving only 1 time 1 which equals 1. In this case you have 4 g/cm3 times 3.0 cm3, cm3's cancel leaving only g as your unit at the end. The rest is for you to solve! Enjoy your problem.

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15y ago
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3w ago

The density of the object is 4.0 g/cm³ and it displaces 3.0 cm³ of water. By using the formula Density = Mass/Volume, we can rearrange it to find the mass: 4.0 g/cm³ = Mass/3.0 cm³, which gives us a mass of 12.0 grams for the object.

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Q: What is the mass of am object with a dessity of 4.0 gcm that displaces 3.0cm of water?
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