mean = sum of dataset / number of items in dataset
= (3 + -10 + -2 + 13 + 11) / 5
= 15/5
= 3
The mean is 3.
3
36
14-2 = 12 12 integers. 2 3 4 5 6 7 8 9 10 11 12 13
It's an even number, so it can't be expressed as the sum of two consecutive integers. You can however do: three consecutive integers: 41 + 42 + 43 four consecutive integers: 30 + 31 + 32 + 33 nine consecutive integers: 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18. twelve consecutive integers: 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
Yes. In the set (9, 10, 11, 12, 13) 11 is the median and the mean.
36
How about the integers of : 10 11 12 13 14 15 ..... to infinity
The question makes no sense.. you can easily find the sum of integers between 1 and 300 but what does 11 or 13 have to do with it.
The integers are 11, 13 and 15.
The integers between 2.09 and 15.3 are 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, and 15. So there are 13 integers between 2.09 and 15.3.
Not in that order. They are consecutive odd integers in this order: 11 13 15.
14-2 = 12 12 integers. 2 3 4 5 6 7 8 9 10 11 12 13
It's an even number, so it can't be expressed as the sum of two consecutive integers. You can however do: three consecutive integers: 41 + 42 + 43 four consecutive integers: 30 + 31 + 32 + 33 nine consecutive integers: 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18. twelve consecutive integers: 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16
It is (8+6+11+12+13)/5 = 10
13
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
Mean: 20.2222222 Median: 12 Mode: 11 Range: 79