Fecr2o4 is the chemical formula for iron(II) chromite, also known as chromite or ferrous chromite. It is a mineral consisting of iron, chromium, and oxygen atoms and is commonly used as a pigment in ceramics and refractory materials.
feCr2O4
To determine the percentage of oxygen in FeCr2O4, you would first calculate the molar mass of the compound (iron(II) chromite) using the atomic masses of each element (Fe = 55.85 g/mol, Cr = 51.996 g/mol, O = 16 g/mol). Then, calculate the molar mass percentages of each element within the compound, and finally, determine the percentage of oxygen by mass in the compound.
Chromium chlorides, Chromite (FeCr2O4), and Chromium oxide (Cr2O3).
The natural state of the element chromium is a solid metal. The natural state just indicates what the element is.
O: 28.59 g x 1 mole O/16 g = 1.79 moles OFe: 24.95 g x 1 mole/55.8 g = 0.447 moles FeCr: 46.46 g x 1 mole/52 g = 0.893 moles CrDividing through by 0.447 one gets 4O, 1Fe and 2CrEmpirical formula = FeCr2O4
It is neither.
It is a mineral.
Is called a mineral
A nonsilicate mineral.
it is mineral because it is our teasure
its a non mineral