Given any number it is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.
However, the only solution based on a polynomial of order 5 is
Un = (11n5 - 195n4 + 1305n3 - 4065n2 + 5704n - 2340)/60 for n = 1, 2, 3, ...
and according to this rule, the next (missing) number is 45.
The missing numbers in the sequence 2 3 4 6 are 5 and 7.
3. Ignore the 8's in the sequence and you get 9, 6, 4, 3,_. 9-3=6 6-2=4 4-1=3 3-0=3
It is7
14
125 (each number is increased by the exponential 3n from the previous: +1, +3, +9, +27, +81)
The missing numbers in the sequence 2 3 4 6 are 5 and 7.
3. Ignore the 8's in the sequence and you get 9, 6, 4, 3,_. 9-3=6 6-2=4 4-1=3 3-0=3
3 It falls between 2 and 4. However, the sequence is incorrect. I believe you mean to do the Fibonacci sequence which is 1,1,2,3,5,8,13.The next number in the series is 16.The numbers are increasing by consecutive integers (+1, +2, +3, +4, +5)
It is7
256
49 The sequence is the squares of numbers that increase by 3 each time: 1² = 1 (1 + 3 )² = 4² = 16 (4 + 3)² = 7² = 49 (7 + 3)² = 10² = 100 (10 + 3)² = 13² = 169
256 (each number is the square of the preceding number)
16
14
Dodging numbers may be missing numbers in a sequence. For example, the underscore in the following sequence represents such a number: 2, 4, _ , 8, 10.
125 (each number is increased by the exponential 3n from the previous: +1, +3, +9, +27, +81)
342