What is the molality of 14.3g of sucrose in 676g of water?

Answer 1

0.0618m

Answer 2

To find the molality, first convert the mass of sucrose to moles by dividing by its molar mass (342.3 g/mol). Then calculate the moles of water in 676g. Finally, divide the moles of sucrose by the kg of water (0.676kg) to get the molality, which would be approximately 0.127 mol/kg.