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Q: What is the molarity of 0.5 liters of a solution with 2.5 moles of sucrose in it?

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Molarity = moles of solute/liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M sucrose solution =================

Molarity = moles of solute/Liters of solution Molarity = 25 moles sucrose/50 liters H2O = 0.5 M sucrose

Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------

since molarity = (number of moles) / (volume of solution), the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water will be 5.11 moles.

I believe the molarity is 1. molarity = number of moles / liters of solution molarity = 3 / 3 = 1

Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M

Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ==================

Molarity = moles of solute/Liters of solution Molarity = 6 moles AgClO4/2 Liters = 3 M AgClO4 =========

Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------

Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------

Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------

Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------

Molarity = moles of solute/Liters of solution Molarity = 2.5 moles NaOH/10 Liters = 0.25 M NaOH ==========

Molarity = moles of solute/Liters of solution ( 500.0 ml = 0.5 Liters ) Molarity = 0.75 moles/0.5 Liters = 1.5 M

Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.

Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========

Molarity = moles of solute/liters of solution Molarity = 7 moles solute/2 Liters solution = 3.5 M ======

Molarity = moles of solute/Liters of solution need to find moles NH3 16.7 grams NH3 (1 mole NH3/17.034 grams) = 0.9804 moles NH3 --------------------------------now Molarity = 0.9804 moles NH3/1.50 Liters = 0.654 M -------------

Molarity or molar concentration is a unit of concentration, symbolized by "M". It is the ratio of the number of moles of solute and the volume of solution (in liters).Molarity = Moles of solute ÷ Liters of solution = moles/liter = Mmolarity is define as the number of mole of a solute in 1 liter of solution.

Molarity = moles of solute/Liters of solution ( 500.0 ml =0.500 Liters ) Molarity = 0.75 moles/0.500 Liters = 1.5 M ----------

M (molarity) = moles of solute/ liters of solution

Molarity = moles solute/ Liters solution

Molarity = moles of solute / liters of solution moles = Molarity x liters = 0.150 x .250 = 0.0375 moles

Molarity = moles of solute/liters of solution or, for our specific purpose here moles of solute (HCl) = liters of solution * Molarity 10 ml = 0.01 liters moles of solute (HCl) = (0.01 liters)*(0.1 M HCl) = 0.001 moles of HCl ------------------------------

Molarity is a measure of the concentration of solute in a solution. It therefore requires moles of solute and liters of solution. The equation is: (moles of solute)/(liters of solution) = Molarity. Some common mistakes are: #forgetting to convert mass or weight into moles #forgetting to convert mass to liters #using milliliters instead of litres