Chemistry

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Molarity = moles of solute/liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M sucrose solution =================

Molarity = moles of solute/Liters of solution Molarity = 25 moles sucrose/50 liters H2O = 0.5 M sucrose

Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------

Molarity = moles of solute/Liters of solution Molarity = 6 moles AgClO4/2 Liters = 3 M AgClO4 =========

Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------

Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------

Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========

Molarity = moles of solute/Liters of solution Molarity = 2.5 moles NaOH/10 Liters = 0.25 M NaOH ==========

Molarity = moles of solute/liters of solution Molarity = 7 moles solute/2 Liters solution = 3.5 M ======

1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============

Molarity = moles of solute/Liters of solution ( 500.0 ml = 0.5 Liters ) Molarity = 0.75 moles/0.5 Liters = 1.5 M

Molarity = moles of solute/Liters of solution ( 500.0 ml =0.500 Liters ) Molarity = 0.75 moles/0.500 Liters = 1.5 M ----------

Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========

since molarity = (number of moles) / (volume of solution), the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water will be 5.11 moles.

Molarity = moles of solute/Liters of solution so, 959 milliliters = 0.959 Liters Molarity = 7.0 moles of solute/0.959 Liters = 7.3 M solute ===========

Molarity = moles of solute/Liters of solution ( 5000 ml = 5 Liters ) Molarity = 90 moles solute/5 Liters = 18 M --------------------the most concentrated possible

Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M

Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ==================

Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============

M (molarity) = moles of solute/ liters of solution

Molarity = moles solute/ Liters solution

Moles of solute/ Liters of solution.

Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============

Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================

Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.

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