Elements and Compounds

# What is the molarity of 23.1 g of NaCl in 725mL of solution?

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Molarity of a solution is defined as the number of moles, or for ionic compounds such as NaCl, gram formula masses, of solute contained in exactly 1 liter of solution. The gram formula mass of NaCl is 58.44, and 725 mL is 0.725 liter. The molarity is therefore [(23.1/58.44)/0.725] or 0.545, to the justified number of significant digits.

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## Related Questions

Factorizations for 231 are: 1) 231 = 1x231 2) 231 = 3x7x11 3) 231 = 21x11 4) 231 = 3x77 5) 231 = 33x7

1,000 gallons.-------------------Solution Method:-------------------1 gallon = 231 cubic inchesThis can also be expressed 1 gal/231 in^3Therefore:231000 in^3 * 1 gallon / 231 in^3 = 1,000 gallonsNote: "in^3" cancel out

There are 4 factor pairs of 231. They are:231 = 1 x 231231 = 3 x 77231 = 7 x 33231 = 11 x 21

Pairs of positive integer factors of 231 are: 1 x 231 = 231 3 x 77 = 231 7 x 33 = 231 11 x 21 = 231 And their reverses.

You can divide 231 by 1, 3, 7, 11, 21, 33, 77, and 231. These are the factors of 231.

55 Percent of 231 = 55/100 * 231 = 127.05.

Least Common Multiple (LCM) for 7 231 is 231.

The composite factors of 231 are 21, 33, 77, 231

The 8 factors of 231 are 1, 3, 7, 11, 21, 33, 77, and 231. The prime factorization of 231 is 231 = 3 * 7 * 11. The prime factors of 231 are 3, 7 and 11.

231 = 3*7*11231 = 3*7*11231 = 3*7*11231 = 3*7*11

I understand that you mean, "what is a 231% increase". This is the same as multiplying the BASE NUMBER by 2.31. For example, 100 increased by 231% would be 231.

The factors of 231 ARE: 1, 3, 7, 11, 21, 33, 77 and 231

The factors of 231 are: 1 3 7 11 21 33 77 231

22 as a percentage of 231 = 100*22/231 = 9.52381 (to 5 dp).

I recognize that 231 is divisible by 3, so when I divide by 3, I get 77.So 231 = 77*3, and 77/231 = 1/3

The factors of 231 are: 1, 3, 7, 11, 21, 33, 77 and 231

###### Math and ArithmeticFactoring and MultiplesPrime Numbers

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