The molarity of a solution containing 7.0 moles of solute in 569mL of solution is
a)81M
b)0.081M
c)12M
D)4.0M
The answer is C. 12M 7 x 1000/569 = 12.302
Molarity= moles of solute/volume of solution in liters, so the problem looks like this: 7/.569, which equals 12.302 M.
Molarity = moles of solute/Liters of solution
so,
959 milliliters = 0.959 Liters
Molarity = 7.0 moles of solute/0.959 Liters
= 7.3 M solute
===========
Molarity = moles of solute/liters of solution
Molarity = 7 moles solute/2 Liters solution
= 3.5 M
======
The molarity of a solution containing 7,0 moles of solute in 523 mL of solution is 4.
The number of mL is not mentioned.
This solution is impossible.
This molarity is 2,33.
The molarity is 7 mol/L.
The concentration in moles of a substance in the solution
The number of moles of a solute per kilogram of solvent. (Apex)
Molarity = moles solute/ Liters solution
moles of solute/L of solution
Molarity is defined as moles solute/liter of solution.Moles of solute = 2.5 moles sucrose Liters of solution = 0.5 liters Molarity (M) = 2.5 moles/0.5 liters = 5 M
Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========
Molarity = moles of solute/Liters of solution Without the solute name the mass ( 8 grams ) does no good. Mass of solute (1 mole/molar mass of solute) = moles solute ----------------------then use Molarity equation. ( remember convert to liters )
Molarity= No. of moles of solute/Volume of solution(in litre) or No. of moles of solute*1000/Volume of solution(in ml)
Molarity means moles in a litre. Therefore you need to divide by 3.95. 1.4/3.95 is 0.35443 molar.
The concentration in moles of a substance in the solution
Molarity = moles solute/ Liters solution
The number of moles of a solute per kilogram of solvent. (Apex)
moles of solute/L of solution
You need to know the moles of solute and the VOLUME of SOLUTION.
Increasing the amount of the solute in the solution the molarity and the density of this solution increases.
Molarity is defined as moles solute/liter of solution.Moles of solute = 2.5 moles sucrose Liters of solution = 0.5 liters Molarity (M) = 2.5 moles/0.5 liters = 5 M
The number of moles of solute dissolved in 1 L of a solution would be the molarity. As an example, if you had 2 moles of solute in 1 liter the molarity would be 2M.