Typically, vinegar is a 5% solution. If 1.0 liter is 1000g (this is only a somewhat close approximation), then 50. g is vinegar and 950 g is water. 50.g divided by 60.06g/mol = 0.8325 mol. Molarity = 0.8325mol/0.950L = 0.87M.
60.05 g/mol
Yes, you could possibly have errors in your data about the molarity of a vinegar sample during a titration experiment if there was an error made during weighing.
That is a question that confuses many. It is because the water is not acidic and therefore does not affect a colour change. You have a known volume of vinegar when starting the experiment.
Molarity is an indication for concentration.
Molarity is an indication for concentration.
the molarity of water is 55.5.
Yes, molarity is (number of moles/liters of solution). If you increase the numerator, the molarity number will be greater.
The number of moles of solute dissolved in 1 L of a solution would be the molarity. As an example, if you had 2 moles of solute in 1 liter the molarity would be 2M.
If you concentrate a solution, the molarity (moles/liter) will increase.
Molarity = Grams/(Molecular Weight X Volume)
Molarity = Grams/(Molecular Weight X Volume)
Yes, molarity is represented by M.
Molarity = moles solute/ Liters solution