KCl + NaNO3 ----> KNO3 + NaCl
The molecular equation for chromium (III) nitrate and potassium phosphate is: 2Cr(NO3)3 + 3K3PO4 -> Cr2(PO4)3 + 9KNO3
NaNO + Kcl =Nacl + KNO3 Further answer But the formula for sodium nitrate is NaNO3, not NaNO.
AgNO3(aq) + KI(aq) = KNO3(aq) + AgI(s) This is a classic test for halogens, and AgI precipitates down as a yellow solid.
The chemical symbol for potassium nitrate is potassium. "KNO3"
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
The balanced equation for Sodium Nitrate (NaNO3) and Potassium Chloride (KCl) is: 2NaNO3 + KCl -> 2NaCl + KNO3
The molecular equation for chromium (III) nitrate and potassium phosphate is: 2Cr(NO3)3 + 3K3PO4 -> Cr2(PO4)3 + 9KNO3
It is impossible to balance that equation.
The net ionic equation for potassium chloride (KCl) and sodium nitrate (NaNO3) is: K+(aq) + NO3-(aq) -> KNO3(aq)
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NaNO + Kcl =Nacl + KNO3 Further answer But the formula for sodium nitrate is NaNO3, not NaNO.
AgNO3(aq) + KI(aq) = KNO3(aq) + AgI(s) This is a classic test for halogens, and AgI precipitates down as a yellow solid.
The chemical symbol for potassium nitrate is potassium. "KNO3"
Molecular mass of sulfuric acid is 98 u. Molecular mass of potassium and nitrate ions are 39 and 62 respectively. The molar mass of potassium nitrate is 101u.
Im not quite sure, but since potassium chloride and ammonium nitrate forms kno3, theoretically, sodium chloride and ammonium nitrate would form sodium nitrate. (Im not 100% sure due to that sodium chloride is more soluble than potassium chloride.)
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
Yes, a white precipitate of lead(II) chloride will form when you mix solutions of potassium chloride and lead nitrate due to the insolubility of lead(II) chloride. The balanced chemical equation for this reaction is: Pb(NO3)2 + 2KCl → PbCl2 + 2KNO3