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The boiling point constant of water is: kb = 0.512. The equation for boiling point elevation is (change in Temp) = kb * Bb where Bb is the molality of the solution taking dissociation into account.

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9y ago
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7y ago

∆T = imK
0.680 = (1)(m)(1.86)
m = 0.366 moles/kg
0.366 moles/Kg = x moles/0.39 kg
x = 0.143 moles
64.3 g/0.143 moles = 450 g/mole = molecular mass

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13y ago

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Q: 64.3 grams of solute in 3.90 X 10Ë grams of water raises the boiling point to 100.680 àC?
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