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p=momentum

m=mass

v=speed (in this case, speed of light)

therefore,

v=c

so start off with:

p=mv

substituting the speed of light you get:

p=mc

to find "m," use E=mc^2

isolate "m" and substitute it into the momentum equation

you get:

p=(E/c^2)c

p=E/c

easy.

now you'll need to turn that 140eV energy value into joules. conversion factor is (1.6*10^-19)

p=E/c

p=(2.24*10^-17)/(3.00*10^8)

p=7.4666666666*10^26

and there's your momentum. (you'll need to add units)

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Q: What is the momentum of a 140 eV photon?
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