What is the momentum of proton moving with speed of 0.86?

Answer 1

We're going to assume that the given number is the proton's rest-mass,

mainly because the solution will be more fun that way.

Rest mass = 1.7 x 10-27

Relativistic mass = (rest-mass) / sqrt [ 1 - v2/c2 ]

Mass at 0.992c = (1.7 x 10-27) / sqrt(0.015936)

Momentum at 0.992c = M V = (1.7 x 10-27)(0.992 x 3 x 108) / sqrt(0.015936) =

(5.0592 x 10-19 / (sqrt(0.015936)

Mass at 0.995c = (1.7 x 10-27) / sqrt(0.009975)

Momentum at 0.995c = M V = (1.7 x 10-27) (0.995 x 3 x 108) / sqrt(0.009975) =

(5.0745 x 10-19) / sqrt(0.009975)

The impulse required is the difference in momentum. Rather than take the reader

through the agony to put both fractions over a common denominator and subtract,

we'll go crunch the numbers off-line, bring back the result, and pray that we're still

within a couple of orders of magnitude.

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In conclusion:

We certainly don't claim to have advanced WikiAnswers to the leading edge

of high-energy Particle Physics. But after subjecting ourselves to this much

fun in pursuit of the answer to a single question, we can't help feeling that

a Trust Point would definitely be in order if our approach has been at all

reasonable.

Answer 2

5.00499 10-19 kg

or

1.66833 * X-27 c

Answer 3

0.86 in what units???In general, you can get the momentum by multiplying mass x velocity.